.TH std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_weekday_last) 3 "2024.06.10" "http://cppreference.com" "C++ Standard Libary"
.SH NAME
std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_weekday_last) \- std::chrono::operator+,std::chrono::operator-(std::chrono::year_month_weekday_last)

.SH Synopsis
   constexpr std::chrono::year_month_weekday_last

       operator+( const std::chrono::year_month_weekday_last& ymwdl,      \fI(since C++20)\fP

                  const std::chrono::months& dm ) noexcept;
   constexpr std::chrono::year_month_weekday_last

       operator+( const std::chrono::months& dm,                          \fI(since C++20)\fP

                  const std::chrono::year_month_weekday_last& ymwdl )
   noexcept;
   constexpr std::chrono::year_month_weekday_last

       operator+( const std::chrono::year_month_weekday_last& ymwdl,      \fI(since C++20)\fP

                  const std::chrono::years& dy ) noexcept;
   constexpr std::chrono::year_month_weekday_last

       operator+( const std::chrono::years& dy,                           \fI(since C++20)\fP

                  const std::chrono::year_month_weekday_last& ymwdl )
   noexcept;
   constexpr std::chrono::year_month_weekday_last

       operator-( const std::chrono::year_month_weekday_last& ymwdl,      \fI(since C++20)\fP

                  const std::chrono::months& dm ) noexcept;
   constexpr std::chrono::year_month_weekday_last

       operator-( const std::chrono::year_month_weekday_last& ymwdl,      \fI(since C++20)\fP

                  const std::chrono::years& dy ) noexcept;

   1,2) Adds dm.count() months to the date represented by ymwdl. The result has the
   same year() and month() as std::chrono::year_month(ymwdl.year(), ymwdl.month()) + dm
   and the same weekday() as ymwdl.
   3,4) Adds dy.count() years to the date represented by ymwdl. The result is
   equivalent to std::chrono::year_month_weekday_last(ymwdl.year() + dy, ymwdl.month(),
   ymwd.weekday_last()).
   5) Subtracts dm.count() months from the date represented by ymwdl. Equivalent to
   ymwdl + -dm.
   6) Subtracts dy.count() years from the date represented by ymwdl. Equivalent to
   ymwdl + -dy.

   For durations that are convertible to both std::chrono::years and
   std::chrono::months, the years overloads (3,4,6) are preferred if the call would
   otherwise be ambiguous.

.SH Example


// Run this code

 #include <cassert>
 #include <chrono>
 using namespace std::chrono;

 int main()
 {
     constexpr auto ymwdl1{Tuesday[last]/11/2021};
     auto ymwdl2 = ymwdl1;
     ymwdl2 = std::chrono::months(12) + ymwdl2;
     ymwdl2 = ymwdl2 - std::chrono::years(1);
     assert(ymwdl1 == ymwdl2);
 }
